## Precalculus (6th Edition)

$(2+4i)(-1+3i)=-14+2i$
$(2+4i)(-1+3i)$ Evaluate the product by multiplying each term of the first factor by every term of the second factor: $(2+4i)(-1+3i)=-2+6i-4i+12i^{2}=...$ Substitute $i^{2}$ by $-1$ and simplify: $...=-2+6i-4i+12(-1)=-2+2i-12=-14+2i$