#### Answer

$(-2+3i)(4-2i)=-2+16i$

#### Work Step by Step

$(-2+3i)(4-2i)$
Evaluate the product by multiplying each term of the first factor by every term of the second factor:
$(-2+3i)(4-2i)=-8+4i+12i-6i^{2}=...$
Substitute $i^{2}$ by $-1$ and simplify:
$...=-8+4i+12i-6(-1)=-8+16i+6=-2+16i$