## Precalculus (6th Edition) Blitzer

Published by Pearson

# Chapter P - Section P.5 - Factoring Polynomials - Exercise Set - Page 68: 41

#### Answer

$(6x-7)(6x+7)$

#### Work Step by Step

The given expression can be written as $(6x)^2-7^2.$ The expression above is a difference of two squares. RECALL: $a^2-b^2=(a-b)(a+b).$ Factor the difference of two squares using the formula above to obtain $(6x-7)(6x+7).$

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