Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Section P.5 - Factoring Polynomials - Exercise Set: 14

Answer

$(x+6)(x^2-2)$

Work Step by Step

Regroup to obtain $(x^3+6x^2)+(-2x-12)$. Factor out $x^2$ in the first group and $-2$ in the second: $x^2(x+6)+(-2)(x+6) \\=x^2(x+6)-2(x+6)$. Factor out $(x+6)$ to obtain $(x+6)(x^2-2)$.
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