Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Section P.5 - Factoring Polynomials - Exercise Set: 15

Answer

$(3x-2)(x^2-2)$

Work Step by Step

Regroup to obtain $(3x^3-2x^2)+(-6x+4)$. Factor out $x^2$ in the first group and $-2$ in the second: $x^2(3x-2)+(-2)(3x-2) \\=x^2(3x-2)-2(3x-2).$ Factor out $(3x-2)$ to obtain $(3x-2)(x^2-2)$.
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