Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Section P.5 - Factoring Polynomials - Exercise Set - Page 68: 25



Work Step by Step

$3x^{2}-25x-28=$ two factors of $ac=-84$ whose sum is $b=-25$ are $-28$ and $+3.$ Rewrite the middle term and factor in pairs. $3x^{2}-25x-28=3x^{2}-28x+3x-28$ $=x(3x-28)+(3x-28)$ $=(3x-28)(x+1)$
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