Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Section P.5 - Factoring Polynomials - Exercise Set - Page 68: 32

Answer

$(9x-4)(x+1)$

Work Step by Step

$9x^{2}+5x-4=$ two factors of $ac=-36$ whose sum is $b=+5$ are $+9$ and $-4.$ Rewrite the middle term and factor in pairs. $9x^{2}+5x-4=9x^{2}+9x-4x-4$ $=9x(x+1)-4(x+1)$ $=(9x-4)(x+1)$
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