Answer
$(3x-1)(3x-2)$
Work Step by Step
$9x^{2}-9x+2=$
two factors of $ac=+18$ whose sum is $b=-9$ are $-6$ and $-3.$
Rewrite the middle term and factor in pairs.
$9x^{2}-9x+2=9x^{2}-6x-3x+2$
$=3(3x-2)-(3x-2)$
$=(3x-1)(3x-2)$
Precalculus (6th Edition) Blitzer
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13446-914-3
ISBN 13:
978-0-13446-914-0
Chapter P - Section P.5 - Factoring Polynomials - Exercise Set - Page 68: 31
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