Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Section P.5 - Factoring Polynomials - Exercise Set: 16

Answer

$(x-1)(x^2-5)$

Work Step by Step

Regroup to obtain $(x^3-x^2)+(-5x+5.)$ Factor out $x^2$ in the first group and $-5$ in the second: $x^2(x-1)+(-5)(x-1) \\=x^2(x-1)-5(x-1).$ Factor out $(x-1)$ to obtain $(x-1)(x^2-5).$
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