Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Section P.5 - Factoring Polynomials - Exercise Set - Page 68: 27



Work Step by Step

$6x^{2}-11x+4=$ two factors of $ac=+24$ whose sum is $b=-11$ are $-8$ and $-3.$ Rewrite the middle term and factor in pairs. $6x^{2}-11x+4=6x^{2}-8x-3x+4$ $=2x(3x-4)-(3x-4)$ $=(2x-1)(3x-4)$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.