Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Section P.5 - Factoring Polynomials - Exercise Set - Page 68: 29



Work Step by Step

$4x^{2}+16x+15=$ two factors of $ac=+60$ whose sum is $b=+16$ are $+6$ and $+10.$ Rewrite the middle term and factor in pairs. $4x^{2}+16x+15=4x^{2}+6x+10x+15$ $=2x(2x+3)+5(2x+3)$ $=(2x+3)(2x+5)$
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