## Precalculus (6th Edition) Blitzer

$260$ feet
Since, $\tan \theta= \dfrac{height}{Adjacent}$ We have the angle of elevation $\theta= 90^{\circ}$ height $=800$ feet $d$ is the distance. Now, $d=800 \times \tan (90^{\circ}) - 72^{\circ}$ or, $d=260$ feet