Answer
Amplitude $=3$ in ; Phase shift $=-\dfrac{1}{2}$ and Period $=2$ s; Frequency $=\dfrac{1}{2}$ in per sec
Work Step by Step
Amplitude, $|A|=|3|=3$
So, $ f=\dfrac{\omega}{2 \pi}=\dfrac{\pi}{2 \pi}=\dfrac{1}{2}$
Now, Phase shift $=\dfrac{-\pi/2}{\pi}=-\dfrac{1}{2}$
and period, $ P=\dfrac{2 \pi}{\omega}=\dfrac{2 \pi}{\pi}=2$
Hence, Amplitude $=3$ in ; Phase shift $=-\dfrac{1}{2}$ and Period $=2$ s; Frequency $=\dfrac{1}{2}$ in per sec