Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 4 - Section 4.8 - Applications of Trigonometric Functions - Exercise Set - Page 638: 38

Answer

Amplitude $=3$ in ; Phase shift $=-\dfrac{1}{2}$ and Period $=2$ s; Frequency $=\dfrac{1}{2}$ in per sec

Work Step by Step

Amplitude, $|A|=|3|=3$ So, $ f=\dfrac{\omega}{2 \pi}=\dfrac{\pi}{2 \pi}=\dfrac{1}{2}$ Now, Phase shift $=\dfrac{-\pi/2}{\pi}=-\dfrac{1}{2}$ and period, $ P=\dfrac{2 \pi}{\omega}=\dfrac{2 \pi}{\pi}=2$ Hence, Amplitude $=3$ in ; Phase shift $=-\dfrac{1}{2}$ and Period $=2$ s; Frequency $=\dfrac{1}{2}$ in per sec
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