## Precalculus (6th Edition) Blitzer

$695$ feet
We have the angle of elevation from a ship to the top of the statue $= 23.7^{\circ}$ height $=305$ feet Now, $\tan ( 23.7^{\circ}) = \dfrac{opposite }{height}$ or, $0.44 = \dfrac{opposite }{height}$ or, $Adjacent=695$ feet It is about $695$ feet away.