Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 4 - Section 4.8 - Applications of Trigonometric Functions - Exercise Set - Page 638: 44


$488$ feet

Work Step by Step

We have the angle of elevation: $\theta= 22.3^{\circ}$ height $=200$ feet Now, $\tan ( 22.3^{\circ}) = \dfrac{height}{Adjacent}$ or, $\tan ( 22.3^{\circ}) = \dfrac{200}{Adjacent}$ or, $ Adjacent=488$ feet
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