Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 4 - Section 4.8 - Applications of Trigonometric Functions - Exercise Set - Page 638: 45


1376 feet

Work Step by Step

Since, $\tan \theta= \dfrac{height}{Adjacent}$ We have the angle of elevation: $\theta= 90^{\circ}$ height $=1000$ feet $ d $ is the distance. Now, $ d=1000 \times \tan (90^{\circ}) -36^{\circ}$ or, $ d=1376$ feet
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