Answer
1376 feet
Work Step by Step
Since, $\tan \theta= \dfrac{height}{Adjacent}$
We have the angle of elevation: $\theta= 90^{\circ}$
height $=1000$ feet
$ d $ is the distance.
Now, $ d=1000 \times \tan (90^{\circ}) -36^{\circ}$
or, $ d=1376$ feet
