## Precalculus (6th Edition) Blitzer

Published by Pearson

# Chapter 4 - Section 4.8 - Applications of Trigonometric Functions - Exercise Set - Page 638: 41

#### Answer

$2059$ feet

#### Work Step by Step

We have a right angled triangle with base $5280$ feet Base angle $= 21.3^{\circ}$ Now, $\tan ( 21.3^{\circ}) = \dfrac{height}{5280}$ height $= 5280 \times \tan ( 21.3^{\circ})$ height = $2059$ feet

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