## Precalculus (6th Edition) Blitzer

$923.55$ or, $924$
Here, we have $x= \dfrac{500}{ \tan 20^{\circ}} - \dfrac{500}{ \tan 48^{\circ}}$ or, $=500( \dfrac{1}{ \tan 20^{\circ}} - \dfrac{1}{ \tan 48^{\circ}})$ or, $=500(2.7475-0.90040)$ So, $x=923.55$ or, $924$