Precalculus (6th Edition) Blitzer

Published by Pearson

Chapter 4 - Section 4.8 - Applications of Trigonometric Functions - Exercise Set - Page 638: 36

Answer

$482$

Work Step by Step

Here, we have $\dfrac{x}{ \tan 43^{\circ}} = \dfrac{x}{ \tan 38^{\circ}}-100$ or, $x= \dfrac{100}{\dfrac{1}{\tan 38^{\circ}}-\dfrac{1}{\tan 43}}$ Simplify the above equation: so, $x=482$

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