Answer
$482$
Work Step by Step
Here, we have $ \dfrac{x}{ \tan 43^{\circ}} = \dfrac{x}{ \tan 38^{\circ}}-100$
or, $ x= \dfrac{100}{\dfrac{1}{\tan 38^{\circ}}-\dfrac{1}{\tan 43}} $
Simplify the above equation:
so, $ x=482$
Precalculus (6th Edition) Blitzer
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13446-914-3
ISBN 13:
978-0-13446-914-0
Chapter 4 - Section 4.8 - Applications of Trigonometric Functions - Exercise Set - Page 638: 36
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