Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 4 - Section 4.8 - Applications of Trigonometric Functions - Exercise Set - Page 638: 35



Work Step by Step

Here, we have $ \dfrac{x}{ \tan 40^{\circ}} = \dfrac{x}{ \tan 20^{\circ}}-400$ or, $ x= \dfrac{400}{\dfrac{1}{\tan 20^{\circ}}-\dfrac{1}{\tan 40}} $ or, $ x= \dfrac{400}{2.7475-1.1918} $ Simplify the above equation: so, $ x=257$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.