Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 4 - Review Exercises - Page 646: 95


The exact value of the provided expression is $0$.

Work Step by Step

Let us assume $\theta ={{\cos }^{-1}}1$. Then, we have $\cos \theta =1$ We know that for the cosine function, the interval for the angle is $\left[ 0,\pi \right]$. So, the only angle that satisfies $\cos \theta =1$ is 0. Thus, $\theta =0$ and the exact value of the given expression is ${{\cos }^{-1}}1=0$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.