Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 4 - Review Exercises - Page 646: 128

Answer

$ y= -30 \sin (\pi x)$

Work Step by Step

Amplitude, $ A=-30$; because the velocity $ v $ is negative. Given: $\omega =\pi $ Now, period, $ P=\dfrac{2 \pi}{\omega}=\dfrac{2 \pi}{\pi }=2$ Hence, the displacement of the particles after $ x $ seconds can be written as: $ y= -30 \sin (\pi x)$
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