Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 4 - Review Exercises - Page 646: 120

Answer

90 yards

Work Step by Step

The trigonometric ratios are as follows: $\sin \theta= \dfrac{opposite}{hypotenuse}$ ; $\cos \theta= \dfrac{Adjacent}{hypotenuse}$ and $\tan \theta= \dfrac{Opposite}{Adjacent}$ Let $ d $ be the difference in the height of the two buildings. Height of the taller building $=d+40$ yards Then: $ d=60 \times \tan 40^{\circ} \approx 50$ yard So, height of the taller building is $50+40= 90$ yards
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