Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 4 - Review Exercises - Page 646: 116

Answer

$ a=7.85 $ and $ c=9.88$ ; and $\angle A=52.6^{\circ}$

Work Step by Step

The trigonometric ratios are as follows: $\sin \theta= \dfrac{opposite}{hypotenuse}$ ; $\cos \theta= \dfrac{Adjacent}{hypotenuse}$ and $\tan \theta= \dfrac{Opposite}{Adjacent}$ $\sin 37.4^{\circ}=\dfrac{6}{c} \implies c=9.88$ and $ a= 6 \cot 37.4^{\circ}=7.85$ So, $\angle A=90^{\circ}- 37.4^{\circ}=52.6^{\circ}$ Thus, $ a=7.85 $ and $ c=9.88$ ; and $\angle A=52.6^{\circ}$
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