Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 4 - Review Exercises - Page 646: 115


$ a=3.79$ ; $ b=9.25 $ and $\angle B=67.7^{\circ}$

Work Step by Step

The trigonometric ratios are as follows: $\sin \theta= \dfrac{opposite}{hypotenuse}$ ; $\cos \theta= \dfrac{Adjacent}{hypotenuse}$ and $\tan \theta= \dfrac{Opposite}{Adjacent}$ $\sin 22.3^{\circ}=\dfrac{a}{10} \implies a=3.79$ and $ b= 10 \cos A=10 \cos 22.3^{\circ}=9.25$ So, $\angle B=90^{\circ}- 22.3^{\circ}=67.7^{\circ}$ Thus, $ a=3.79$ ; $ b=9.25 $ and $\angle B=67.7^{\circ}$
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