Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 4 - Review Exercises - Page 646: 129


$ y= -\dfrac{1}{4} \sin (\dfrac{2 \pi x}{5})$

Work Step by Step

Amplitude, $ A=-\dfrac{1}{4}$. It is negative because the object is "pulled down". Now, period, $ P=\dfrac{2 \pi}{\omega}=5$ $\implies \omega=\dfrac{2 \pi}{5}$ Hence, the displacement of the particles after $ x $ seconds can be written as: $ y= -\dfrac{1}{4} \sin (\dfrac{2 \pi x}{5})$
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