Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 4 - Review Exercises - Page 646: 104

Answer

The exact value of the provided expression is $2$.

Work Step by Step

Let us assume $\theta ={{\tan }^{-1}}\left( \frac{\sqrt{3}}{3} \right)$. Then, $\tan \theta =\frac{\sqrt{3}}{3}$ We know that for the tan function, the interval for the angle is $\left( -\frac{\pi }{2},\frac{\pi }{2} \right)$. Therefore, the only angle that satisfies $\tan \theta =\frac{\sqrt{3}}{3}$ is $\left( \frac{\pi }{6} \right)$. Hence, $\theta =\left( \frac{\pi }{6} \right)$ and the exact value of the given expression is $\begin{align} & \csc \left[ {{\tan }^{-1}}\left( \frac{\sqrt{3}}{3} \right) \right]=\csc \left( \theta \right) \\ & =\csc \left( \frac{\pi }{6} \right) \\ & =2 \end{align}$
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