Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 4 - Review Exercises - Page 646: 127

Answer

a. $\frac{1}{2}\ cm$ b. $\frac{2}{\pi}\ Hz$ (cycles per second) c. $ \frac{\pi}{2}\ sec$.

Work Step by Step

a. The maximum displacement is the same as the amplitude, which is $\frac{1}{2}\ cm$ based on the given equation. b. The frequency $f$ can be found from the given equation as $\omega=2\pi f=4$; thus $f=\frac{2}{\pi}\ Hz$ (cycles per second) c. The time required for one cycle is the same as the period, which is $p=\frac{1}{f}= \frac{\pi}{2}\ sec$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.