Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 4 - Review Exercises - Page 646: 121


$21.67$ feet

Work Step by Step

The trigonometric ratios are as follows: $\sin \theta= \dfrac{opposite}{hypotenuse}$ ; $\cos \theta= \dfrac{Adjacent}{hypotenuse}$ and $\tan \theta= \dfrac{Opposite}{Adjacent}$ Let $ a $ be the height of the antenna. Height of the taller building $=d+40$ yards Then: $ d=125 \times \cot 68^{\circ} $ and $ d=(125+a) \cot 71^{\circ}$ So, $ a=\dfrac{125 ( \cot 68^{\circ} -\cot 71^{\circ})}{\cot 71^{\circ}}=21.67 feet $
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