Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 10 - Review Exercises - Page 1124: 5


$ a_1=9,a_2=\dfrac{2}{27}, a_3=9; a_4=\dfrac{2}{27}$

Work Step by Step

The general formula to find the nth term of a Geometric sequence is given as: $ a_{n}=a_1r^{n-1}$ In order to calculate the General formula of a Geometric sequence we will multiply the first term $ a_1$ by the product of the common ratio with itself one unit less then a Geometric sequence. In order to calculate the first $4$ terms of the sequence we will have to plug $ n=1,2,3,4$ into the given equation; by doing so we get a recursive equation and we continue this to get the higher order terms. So, we get $ a_1=9,a_2=\dfrac{2}{27}, a_3=9; a_4=\dfrac{2}{27}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.