Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 10 - Review Exercises - Page 1124: 11

Answer

$S=\sum_{i=1}^{10}(i+3)^3$

Work Step by Step

Step 1. Let $a_1=4=1+3, a_2=5=2+3, a_3=6=3+3 $. We have $a_{10}=13=10+3$ and $a_{n}=n+3$ Step 2. We can express the summation as $S=\sum_{i=1}^{10}(i+3)^3$
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