Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 10 - Review Exercises - Page 1124: 29



Work Step by Step

We need to use the formula $ a_n =a_1+(n-1) d $ Here, $ a_1=31,500$ and $ d=2300$ $ a_{n}=31,500 +(n-1) \times (2300) =29,200+2300n $ or, $ a_{10}=29,200+2300 \times 10=52,200$ Now, $ S_{10}=\dfrac{10(31,500+52,200)}{2}=418,500$
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