Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 10 - Review Exercises - Page 1124: 15


$ a_1=-2;a_2 =3, a_3=8; a_4=13; a_5=18: a_6=23$

Work Step by Step

We need to use the formula $ a_n =a_1+(n-1) d $ ....(1) Here, $ a_1=-2$ and $ n=6$ and $ d=1$ $ a_2=-2 +(6-1) \times 1 =-2+5=3$ We make use of the recursive formula to get higher order terms. So, the first $6$ terms are: $ a_1=-2;a_2 =3, a_3=8; a_4=13; a_5=18: a_6=23$
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