Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 10 - Review Exercises - Page 1124: 24

Answer

$15150$

Work Step by Step

We need to use the formula $ S_n=\dfrac{n(a_1+a_2)}{2}$ Here, $ a_1=3$ and $ n=100$ Now, $ S_n=\dfrac{n(a_1+a_2)}{2}$ and $ S_{100}=\dfrac{100(3+300)}{2}=15150$
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