Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 10 - Review Exercises - Page 1124: 33


$ a_{1}=16;a_2=-8;a_3=4;a_4=-2;a_5=1$

Work Step by Step

The general formula to find the nth term of a Geometric sequence is given as: $ a_{n}=a_1r^{n-1}$ Here, $ a_n=16(-\dfrac{1}{2})^{n-1}$ Plug $ n=1,2,3,4,5$ $ a_{1}=16(-\dfrac{1}{2})^{1-1}=16;a_2=16(-\dfrac{1}{2})^{2-1}=-8;a_3=16(-\dfrac{1}{2})^{3-1}=4;a_4=16(-\dfrac{1}{2})^{4-1}=-2;a_5=16(-\dfrac{1}{2})^{5-1}=1$ So, the first $5$ terms of the sequence are $ a_{1}=16;a_2=-8;a_3=4;a_4=-2;a_5=1$
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