## Precalculus (6th Edition) Blitzer

Published by Pearson

# Chapter 10 - Review Exercises - Page 1124: 4

#### Answer

$a_1=\dfrac{1}{2},a_2=\dfrac{-1}{4}, a_3=\dfrac{1}{8}; a_4=\dfrac{-1}{16}$

#### Work Step by Step

The general formula to find the nth term of a Geometric sequence is given as: $a_{n}=a_1r^{n-1}$ In order to calculate the General formula of a Geometric sequence we will multiply the first term $a_1$ by the product of the common ratio with itself one unit less then a Geometric sequence. In order to calculate the first $4$ terms of the sequence we will have to plug $n=1,2,3,4$ into the given equation. So, we get $a_1=\dfrac{1}{2},a_2=\dfrac{-1}{4}, a_3=\dfrac{1}{8}; a_4=\dfrac{-1}{16}$

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