Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 10 - Review Exercises - Page 1124: 12

Answer

$ a_1=7;a_2 =11, a_3= 15; a_4=19; a_5= 23: a_6=27$

Work Step by Step

We need to use the formula: $ a_n =a_1+(n-1) d $ ....(1) Here, $ a_1=7$ and $ d=4$ Plug in: $ n=1,2,3,4,5,6$ In order to calculate the first $6$ terms of the sequence, we will have to plug $ n=1,2,3,4$ into the given equation (1). $ a_1=7 +(1-1) \times 4 =7; a_2=7 +(2-1) \times 4 =7+4=11$; $ a_3=7 +(3-1) \times 4 =15$ ; $ a_4=7 +(4-1) \times 4 =19$; $ a_5=7 +(5-1) \times 4 =23$ ; $ a_6=7 +(6-1) \times 4 =7+20=27$ So, the first $6$ terms are: $ a_1=7;a_2 =11, a_3= 15; a_4=19; a_5= 23: a_6=27$
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