Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 7 - Analytic Trigonometry - 7.6 Double-angle and Half-angle Formulas - 7.6 Assess Your Understanding - Page 498: 66

Answer

See below.

Work Step by Step

$LHS=\frac{(cos\theta+sin\theta)^2-(cos\theta-sin\theta)^2}{(cos\theta-sin\theta)(cos\theta+sin\theta)}=\frac{(2cos\theta)(2sin\theta)}{cos^2\theta-sin^2\theta}=\frac{2sin(2\theta)}{cos(2\theta)}=2tan(2\theta)=RHS$
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