Answer
See below.
Work Step by Step
$LHS=tan(\frac{\theta}{2})=\frac{1-cos\theta}{sin\theta}=\frac{1}{sin\theta}-\frac{cos\theta}{sin\theta}=csc\theta-cot\theta=RHS$
Here $\theta=v$
Precalculus (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0-32197-907-9
ISBN 13:
978-0-32197-907-0
Chapter 7 - Analytic Trigonometry - 7.6 Double-angle and Half-angle Formulas - 7.6 Assess Your Understanding - Page 498: 62
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