Answer
See below.
Work Step by Step
$LHS=\frac{sin(3\theta)cos\theta-cos(3\theta)sin\theta}{sin\theta cos\theta}=\frac{sin(3\theta-\theta)}{sin\theta cos\theta}=\frac{2sin\theta cos\theta}{sin\theta cos\theta}=2=RHS$
Precalculus (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0-32197-907-9
ISBN 13:
978-0-32197-907-0
Chapter 7 - Analytic Trigonometry - 7.6 Double-angle and Half-angle Formulas - 7.6 Assess Your Understanding - Page 498: 65
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
