Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 7 - Analytic Trigonometry - 7.6 Double-angle and Half-angle Formulas - 7.6 Assess Your Understanding - Page 498: 63

Answer

See below.

Work Step by Step

$RHS=\frac{1-sin^2(\frac{\theta}{2})/cos^(\frac{\theta}{2})}{1+sin^2(\frac{\theta}{2})/cos^(\frac{\theta}{2})}=\frac{cos^2(\frac{\theta}{2})-sin^2(\frac{\theta}{2})}{cos^2(\frac{\theta}{2})+sin^2(\frac{\theta}{2})}=\frac{cos\theta}{1}=cos\theta=LHS$
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