Answer
See below.
Work Step by Step
$sin^2(\frac{\theta}{2})=\frac{1-cos\theta}{2}\longrightarrow csc^2(\frac{\theta}{2})=\frac{1}{sin^2(\frac{\theta}{2})}=\frac{2}{1-cos\theta}$
Precalculus (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0-32197-907-9
ISBN 13:
978-0-32197-907-0
Chapter 7 - Analytic Trigonometry - 7.6 Double-angle and Half-angle Formulas - 7.6 Assess Your Understanding - Page 498: 60
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
