Answer
See below.
Work Step by Step
$RHS=\frac{1}{8}[1-(1-2sin^2(2\theta))]=\frac{1}{4}[sin^2(2\theta)]=\frac{1}{4}[2sin\theta cos\theta]^2=sin^2\theta cos^2\theta=LHS$
Precalculus (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0-32197-907-9
ISBN 13:
978-0-32197-907-0
Chapter 7 - Analytic Trigonometry - 7.6 Double-angle and Half-angle Formulas - 7.6 Assess Your Understanding - Page 498: 58
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