Answer
See below.
Work Step by Step
$RHS=\frac{cos^2\theta/sin^2\theta-1}{2cos\theta/sin\theta}\times\frac{sin^2\theta}{sin^2\theta}=\frac{cos^2\theta-sin^2\theta}{2sin\theta cos\theta}=\frac{cos(2\theta)}{sin(2\theta)}=cot(2\theta)=LHS$
Precalculus (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0-32197-907-9
ISBN 13:
978-0-32197-907-0
Chapter 7 - Analytic Trigonometry - 7.6 Double-angle and Half-angle Formulas - 7.6 Assess Your Understanding - Page 498: 51
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