Answer
$48384x^3.$
Work Step by Step
According to the Binomial Theorem, the nth term in the expansion of $(bx+a)^k$ is given by: ${k\choose k-n+1}a^{n-1}(bx)^{k-n+1}.$
Hence here for $n=6,k=8$: ${8\choose 8-6+1}(2)^{6-1}(3x)^{8-6+1}={8\choose 3}(2)^{5}(3x)^{3}=48384x^3.$