Answer
$32x^5+240x^4+720x^3+1080x^2+810x+243$
Work Step by Step
We are given the expression:
$(2x+3)^5$
Use the Binomial Theorem to expand the expression:
$(2x+3)^5=\sum_{k=0}^5 \binom{5}{k}(2x)^{5-k}3^k$
$=\binom{5}{0}(2x)^53^0+\binom{5}{1}(2x)^43^1+\binom{5}{2}(2x)^33^2+\binom{5}{3}(2x)^23^3+\binom{5}{4}(2x)^13^4+\binom{5}{5}(2x)^03^5$
$=32x^5+5(16)(3)x^4+10(8)(9)x^3+10(4)(27)x^2+5(2)(81)x+243$
$=32x^5+240x^4+720x^3+1080x^2+810x+243$
