## Precalculus (10th Edition)

$1760.$
According to the Binomial Theorem, the term containing $x^j$ in the expansion of $(ax+b)^n$ is given by: ${n\choose n-j}a^jb^{n-j}x^j.$ Hence here for $x^3$: ${12\choose 12-3}2^3(1)^{12-3}=1760.$