Answer
False.
Work Step by Step
For $n\choose j$ the correct formula is $\dfrac{n!}{(n-j)!j!}$, hence the statement is false.
Precalculus (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0-32197-907-9
ISBN 13:
978-0-32197-907-0
Chapter 12 - Sequences; Induction; the Binomial Theorem - 12.5 The Binomial Theorem - 12.5 Assess Your Understanding - Page 836: 3
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