Answer
$x^5+5x^4+10x^2+5x+1$
Work Step by Step
We are given the expression:
$(x+1)^5$
Use the Binomial Theorem to expand the expression:
$(x+1)^5=\sum_{k=0}^5 \binom{5}{k}x^{5-k}1^k$
$=\binom{5}{0}x^5+\binom{5}{1}x^4+\binom{5}{2}x^3+\binom{5}{3}x^2+\binom{5}{4}x^1+\binom{5}{5}$
$=x^5+5x^4+10x^2+5x+1$