Answer
$314928x^7.$
Work Step by Step
According to the Binomial Theorem, the nth term in the expansion of $(bx+a)^k$ is given by: ${k\choose k-n+1}a^{n-1}(bx)^{k-n+1}.$
Hence here for $n=3,k=9$: ${9\choose 9-3+1}(-2)^{3-1}(3x)^{9-3+1}={9\choose 7}(-2)^{2}(3x)^{7}=314928x^7.$